pythonfunctionarguments

Pass each element of a list to a function that takes multiple arguments in Python?

For example, if I have

a=[['a','b','c'],[1,2,3],['d','e','f'],[4,5,6]]

How can I get each element of a to be an argument of say, zip without having to type

zip(a[0],a[1],a[2],a[3])?

Solution

  • Using sequence unpacking (thanks to delnan for the name):

    zip(*a)