How can I emulate a 'break' or even a 'continue' inside a 'forEach' loop?

Here is what I would like to do. However there's no "continue" inside a forEach.

    var que = null
    self.qs.forEach((q) => {
        if (q.synchronized == false) {
            que = q;
            break; // I would like to do this
        }
    });
    //  Now que would be set to the first not synchronized

Can anyone tell me how I can do this. Note that I am using the latest browsers. Please note I am only looking for one object in the array where synchronized == true. Sorry I used "continue" in my question earlier. The functionality I am looking for is "break".

you can use Array.prototype.some:

short form:

self.qs.some((q) => {
   return (q.synchronized == false) && (que = q, true);
});

or:

self.qs.some((q) => {
   if (q.synchronized == false)
   {
      que = q;
      return true;
   }
});

or:

self.qs.some(q => (q.synchronized == false) && (que = q, true));

Array.prototype.some returns on the first result that returns true.

Array.prototype.every returns on the first result that returns false.

They are basically tests for:

• some: does at least 1 item return true
• every: does every item return true

You can abuse this for something you want here :-)

The 3rd example is a bit of JS-fu but generates a nice oneliner ^_^

full code:

var que;
self.qs.some((q) => {
   if (q.synchronized == false)
   {
      que = q;
      return true;
   }
});
if (que) {
   // handle que here
}

Unoptimized dirty hack:

You could also use reduce for this:

var que = self.qs.reduce((result, q) => {
    if (que != null) return result;
    return (q.synchronized == false) ? q : result;
}, null);
// js-fu version
var que = self.qs.reduce((result,q) => que || (q.synchronized == false ? q : que),null);

Very unoptimized, but it saves you defining a var... It has no early out though.