Why does a js map on an array modify the original array?

I'm quite confused by the behavior of map().

I have an array of objects like this:

const products = [{
    ...,
    'productType' = 'premium',
    ...
}, ...]

And I'm passing this array to a function that should return the same array but with all product made free:

[{
    ...,
    'productType' = 'free',
    ...
}, ...]

The function is:

const freeProduct = function(products){
    return products.map(x => x.productType = "free")
}

Which returns the following array:

["free", "free", ...]

So I rewrote my function to be:

const freeProduct = function(products){
    return products.map(x => {x.productType = "free"; return x})
}

Which returns the array as intended.

BUT ! And that's the moment where I loose my mind, in both cases my original products array is modified.

Documentation around map() says that it shouldn't ( https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map ).

I even tried to create a clone of my array turning my function into this:

const freeProduct = function(products){
    p = products.splice()
    return p.map(x => {x.productType = "free"; return x})
}

But I still get the same result (which starts to drive me crazy).

I would be very thankful to anyone who can explain me what I'm doing wrong!

Thank you.

You're not modifying your original array. You're modifying the objects in the array. If you want to avoid mutating the objects in your array, you can use Object.assign to create a new object with the original's properties plus any changes you need:

const freeProduct = function(products) {
  return products.map(x => {
    return Object.assign({}, x, {
      productType: "free"
    });
  });
};

2018 Edit:

In most browsers you can now use the object spread syntax instead of Object.assign to accomplish this:

const freeProduct = function(products) {
  return products.map(x => {
    return {
      ...x,
      productType: "free"
    };
  });
};