I'm trying to write a function to present thousands and millions into K's and M's For instance:
1000 = 1k
1100 = 1.1k
15000 = 15k
115000 = 115k
1000000 = 1m
Here is where I got so far:
func formatPoints(num: Int) -> String {
let newNum = String(num / 1000)
var newNumString = "\(num)"
if num > 1000 && num < 1000000 {
newNumString = "\(newNum)k"
} else if num > 1000000 {
newNumString = "\(newNum)m"
}
return newNumString
}
formatPoints(51100) // THIS RETURNS 51K instead of 51.1K
How do I get this function to work, what am I missing?
func formatPoints(num: Double) ->String{
let thousandNum = num/1000
let millionNum = num/1000000
if num >= 1000 && num < 1000000{
if(floor(thousandNum) == thousandNum){
return("\(Int(thousandNum))k")
}
return("\(thousandNum.roundToPlaces(1))k")
}
if num > 1000000{
if(floor(millionNum) == millionNum){
return("\(Int(thousandNum))k")
}
return ("\(millionNum.roundToPlaces(1))M")
}
else{
if(floor(num) == num){
return ("\(Int(num))")
}
return ("\(num)")
}
}
extension Double {
/// Rounds the double to decimal places value
func roundToPlaces(places:Int) -> Double {
let divisor = pow(10.0, Double(places))
return round(self * divisor) / divisor
}
}
The updated code should now not return a .0 if the number is whole. Should now output 1k instead of 1.0k for example. I just checked essentially if double and its floor were the same.
I found the double extension in this question: Rounding a double value to x number of decimal places in swift