apachetomcat6mod-jk

Apache httpd 2.2.x + mod_jk 1.2.30 + tomcat 6 Error: Could not find worker with name 'XXXXX' in uri map post processing


I am getting the following error while setting up the load balancer with two Tomcat instances:

[info] mod_jk.c (3189): mod_jk/1.2.30 initialized [error] jk_uri_worker_map.c (506): Could not find worker with name 'loadmanager' in uri map post processing.

Following are my configuration settings:

httpd.conf changes

# Include mod_jk configuration file
Include conf/mod_jk.conf

mod_jk.conf

LoadModule jk_module modules/mod_jk.so    
JkWorkersFile conf/workers.properties    
JkLogFile logs/mod_jk.log    
JkLogLevel info    
JkLogStampFormat  "[%a %b %d %H:%M:%S %Y]"    
JkOptions +ForwardKeySize +ForwardURICompat -ForwardDirectories    
JkRequestLogFormat "%w %V %T"    
JkMount /TestLB1/ loadmanager    
JkMount /TestLB1/* loadmanager    
JkShmFile logs/jk.shm

workers.properties

worker.list=loadmanager

worker.tomcat1.port=18081
worker.tomcat1.host=localhost
worker.tomcat1.type=ajp13
worker.tomcat1.lbfactor=1

worker.tomcat2.port=28081
worker.tomcat2.host=localhost
worker.tomcat2.type=ajp13
worker.tomcat2.lbfactor=1

worker.loadmanager.type=lb
worker.loadmanager.balance_workers=tomcat1,tomcat2
worker.loadmanager.sticky_session=True

In Tomcat's server.xml I have set the jvmRoute attribute to Engine also

 <Engine defaultHost="localhost" name="Catalina" jvmRoute="tomcat1">
 <Engine defaultHost="localhost" name="Catalina" jvmRoute="tomcat2">

Both the Tomcat instances are up and running fine with AJP ports 18081 & 28081 respectively.

But while starting the Apache httpd.exe the mod_jk log files always shows the above error, and when I try to access my web app through http://localhost/TestLB1 nothing comes up.

Any Solution?


Solution

  • Got the problem.... Issues is with the text editor in which i was editing my worker.properties file , it adds few special chars to files. I found them when i opend the files in notepad only. After removing all unwanted chars everythings works perfect.