Here:
#include <iostream>
#include <cstdlib>
#include <boost/lexical_cast.hpp>
int main(void) {
const char * str = "277499.84";
std::cout << boost::lexical_cast<double>(str) << std::endl;
std::cout << strtof(str, NULL) << std::endl;
std::cout << strtold(str, NULL) << std::endl;
std::cout << atof(str) << std::endl;
return 0;
}
output:
277500
277500
277500
277500
Why the output are not 277499.84?
It's not the operations themselves losing accuracy, but the output.
You can use the I/O manipulator std::setprecision
to control the numeric precision. The following will use the full precision of a double (assuming the stream is set for decimal output).
double value = boost::lexical_cast<double>(str);
std::cout << std::setprecision( std::numeric_limits<double>::digits10 + 1 ) << value;
Or you can use std::ios_base::precision
. This is useful if you want to restore the precision to the original value after.
auto old_precision = cout.precision( std::numeric_limits<double>::digits10 + 1 );
cout << value;
cout.precision( old_precision );