I have a script:
newerthan="2016-02-08"
olderthan="2016-04-29"
find / -type f -name "*" -newermt "$newerthan" ! -newermt "$olderthan" -ls
This list files:
16481 0 -r--r--r-- 1 root root 4096 Mar 16 11:41 /sys/module/sunrpc/srcversion
16482 0 -r--r--r-- 1 root root 4096 Mar 13 04:42 /sys/module/sunrpc/initstate
16483 0 -r--r--r-- 1 root root 4096 Mar 16 11:41 /sys/module/sunrpc/refcnt
16485 0 -r--r--r-- 1 root root 4096 Mar 17 11:41 /sys/module/sunrpc/sections/.note.gnu.build-id
16486 0 -r--r--r-- 1 root root 4096 Mar 12 11:41 /sys/module/sunrpc/sections/.text
Is it possible to sort by date, the result ?
If you want to print the filenames along with the date in sorted order:
find / -type f -name "*" -newermt "$newerthan" ! -newermt "$olderthan" -printf "%T+\t%p\n" | sort
If you want to print only the filenames in sorted order:
find / -type f -name "*" -newermt "$newerthan" ! -newermt "$olderthan" -printf "%T+\t%p\n" | sort | awk '{print $2}'