caddress-operator

What is the difference between &p and p

if I have a pointer to an integer such as:

int num = 12;
int *p = #

and then print the address so

printf("%p\n", (void*)p);

What is the difference between the previous and this:

printf("%p\n", (void*)&p);
Solution

  • Here, p contains the address of num, so the first printf outputs the address of num.

    On the other hand, &p is the address of p, so the second printf prints the address of p.