I am researching how python implements dictionaries. One of the equations in the python dictionary implementation relates the pseudo random probing for an empty dictionary slot using the equation
j = ((j*5) + 1) % 2**i
which is explained here.
I have read this question, How are Python's Built In Dictionaries Implemented?, and basically understand how dictionaries are implemented.
What I don't understand is why/how the equation:
j = ((j*5) + 1) % 2**i
cycles through all the remainders of 2**i
. For instance, if i = 3
for a total starting size of 8. j
goes through the cycle:
0
1
6
7
4
5
2
3
0
if the starting size is 16, it would go through the cycle:
0 1 6 15 12 13 2 11 8 9 14 7 4 5 10 3 0
This is very useful for probing all the slots in the dictionary. But why does it work ? Why does j = ((j*5)+1)
work but not j = ((j*6)+1)
or j = ((j*3)+1)
both of which get stuck in smaller cycles.
I am hoping to get a more intuitive understanding of this than the equation just works and that's why they used it.
This is the same principle that pseudo-random number generators use, as Jasper hinted at, namely linear congruential generators. A linear congruential generator is a sequence that follows the relationship X_(n+1) = (a * X_n + c) mod m
. From the wiki page,
The period of a general LCG is at most m, and for some choices of factor a much less than that. The LCG will have a full period for all seed values if and only if:
m
andc
are relatively prime.a - 1
is divisible by all prime factors ofm
.a - 1
is divisible by 4 ifm
is divisible by4
.
It's clear to see that 5 is the smallest a
to satisfy these requirements, namely
Also interestingly, 5 is not the only number that satisfies these conditions. 9 will also work. Taking m
to be 16, using j=(9*j+1)%16
yields
0 1 10 11 4 5 14 15 8 9 2 3 12 13 6 7
The proof for these three conditions can be found in the original Hull-Dobell paper on page 5, along with a bunch of other PRNG-related theorems that also may be of interest.