Python reading Wiegand dropping Zeros

Here's the code snippet from my RFID wiegand reader on my Raspberry Pi I use already.

def main():
    set_procname("Wiegand Reader")
    global bits
    global timeout
    GPIO.add_event_detect(D0, GPIO.FALLING, callback=one)
    GPIO.add_event_detect(D1, GPIO.FALLING, callback=zero)
    GPIO.add_event_detect(S1, GPIO.FALLING, callback=unlockDoor)
    while 1:
        if bits:
            timeout = timeout -1
            time.sleep(0.001)
            if len(bits) > 1 and timeout == 0:
                #print "Binary:", int(str(bits),2)
                c1 = int(str(bits),2)
                result = ((~c1) >> 1) & 0x0FFFFFF;
                checkAccess(result, doorID)
        else:
            time.sleep(0.001)



    if __name__ == '__main__':
        main()

On a normal USB RFID reader, I get 0000119994 and that's what's printed on the card. But with this code it reads 119994. I've tried multiple cards. It always drops the zeros at the front .

I even tried a card with a zero in it. 0000120368 and it shows 120368 I thought it was taking off the first 4 characters but then I tried a key fob that only had 3 zeros in front. 0004876298 and it reads 4876298. Only dropping the front zeros.

Python will remove the front few bits if they are zero, this also applies to integers. For example

>>> a = 0003
>>> a
3
>>> b = 0b0011
>>> bin(b)
0b11

From what I see, all RFID's will have 10 numbers. You can make a simple program to add those numbers in and store the value as a string:

def rfid_formatter(value):
    str_value = str(value)
    for s in range(10 - len(str_value)):
        str_value = "0" + str_value
    return str_value

Your test cases:

print rfid_formatter(120368)
print "0000120368"
print rfid_formatter(4876298)
print "0004876298"