In Python I can do:
a = array([[1,2],[3,4]])
row1, row2 = a
Is there an equivalent one-liner in Julia? This doesn't seem to work:
a = [[1 2]; [3 4]]
row1, row2 = a
Instead it sets row1=1 and row2=3. Thanks!
Depending on what you are doing you could use a Vector{Vector{T}}, like python list of lists instead of a Matrix (Array{T,2}).
In v0.5+ it just works, with [ , ]:
julia> VERSION
v"0.5.0-dev+4440"
julia> a = [[1, 2], [3, 4]]
2-element Array{Array{Int64,1},1}:
[1, 2]
[3, 4]
julia> a = [[1, 2]; [3, 4]]
4-element Array{Int64,1}:
1
2
3
4
julia> row1, row2 = a;
julia> (row1, row2)
(2-element Array{Int64,1}:
1
2,2-element Array{Int64,1}:
3
4)
In v0.4+ you need to type the array as an array of arrays, like so:
julia> VERSION
v"0.4.5"
julia> a = Vector[[1, 2], [3, 4]]
2-element Array{Array{T,1},1}:
[1,2]
[3,4]
julia> b = [[1, 2]; [3, 4]]
4-element Array{Int64,1}:
1
2
3
4
julia> c = [[1, 2], [3, 4]]
WARNING: [a,b] concatenation is deprecated; use [a;b] instead
in depwarn at deprecated.jl:73
in oldstyle_vcat_warning at abstractarray.jl:29
in vect at abstractarray.jl:32
while loading no file, in expression starting on line 0
4-element Array{Int64,1}:
1
2
3
4
julia> row1, row2 = a;
julia> row1, row2
([1,2],[3,4])