pythoncomparison-operators

Are there 'not less than' or 'not greater than' (!> or !<) operators in python?

Suppose I have this code to do something when a is not negative number:

a = 0
if a == 0 or a > 0:
    print(a)

That is: I want to do something when a is either equal to or greater than 0 (meaning it is not a negative number).

I know that I can write if a != 0: to check whether a is not equal to 0.

So, I tried using if a !< 0:, following similar logic. However, this is apparently not a valid operator:

>>> if a !< 0:
  File "<stdin>", line 1
    if a !< 0:
         ^
SyntaxError: invalid syntax

What can I use to simplify the conditional statement and just say 'if a is not less than 0'?

Solution

  • Instead of a == 0 or a > 0, simply use a >= 0.

    See https://docs.python.org/library/stdtypes.html#comparisons for a complete list of available comparison operators.