Since js.Dynamic.literal() != js.Dynamic.literal(),
what is the suggested way to test equality for two literals?
I don't want to characterize those literals with traits. I want to know if they are deeply equal.
What I'm doing right now is the following
val js1 = literal()
val js2 = literal()
val json1 = JSON.stringify(js1)
val json2 = JSON.stringify(js2)
assert(json1 == json2) // true
Note: even in javascript {} === {}
evaluates to false, so I shouldn't have been surprised in the first place.
You could define your own structural equality for JS object-like structures:
def jsStructuralEqual(a: Any, b: Any): Boolean = {
(a, b) match {
case (a: js.Array[_], b: js.Array[_]) =>
a.length == b.length &&
a.zip(b).forall((jsStructuralEqual _).tupled)
case _ if a.constructor == js.constructorOf[js.Object] &&
b.constructor == js.constructorOf[js.Object] =>
val aDict = a.asInstanceOf[js.Dictionary[Any]]
val bDict = b.asInstanceOf[js.Dictionary[Any]]
(aDict.keySet == bDict.keySet) &&
aDict.keySet.forall(key => jsStructuralEqual(aDict(key), bDict(key))
case _ =>
a == b
}
}
(not tested)