How to Access a Local Variable in a Different Scope in C++?

In C++, I have a situation where I want to access a variable defined in the local scope of the main function from an inner block scope. Here’s a simplified version of my code:

#include <iostream>
using namespace std;

int var = 10;  // Global variable

int main(int argc, char *argv[])
{
    int var = 20;  // Local variable in main
    {
        int var = 40;  // Local variable in inner block

        cout << ::var;  // Prints 10 (the global variable)
                         // But I want to print the `var` in the `main` scope (20)
    }

    return 0;
}

I want cout to print 20, which is the value of var in the scope of main. However, using ::var only gives me the global variable value 10.

Is there a way in C++ to access the local variable in main (value 20) from within this inner block, bypassing the local variable defined in the inner block (value 40)?

I know that C++ doesn’t have an equivalent of Python’s nonlocal keyword, but is there a workaround or technique that allows accessing a variable from an enclosing scope without changing the variable names?

There is no way to accomplish that. The language does not provide a way to differentiate between the first var in main from the second var.

If you ever write production code, please refrain from using such variables. It will lead to buggy code. You will be confused about which variable is in scope in a given line of code.