Swift 3, Xcode 8β2.
I've implemented a class that sorts Comparable data and attempted to test it using Doubles. Unfortunately, I'm getting the error "Cannot convert value of type '[Double]' to specified type '[T]'.". I've reproduced the error in the sample code below:
class foo<T: Comparable> {
let data: [T] = [Double]()
}
Am I right is assuming that Doubles are Comparable and, if so, how do I eliminate the error above?
Thx.
Your property has a generic type, T: it can't be declared as holding a concrete type. Just use [T] in the declaration, and use Double when instantiating the class.
For my example I've also made the property a var so that I could modify it:
class Foo<T: Comparable> {
var data: [T] = [T]()
}
let f = Foo<Double>()
f.data = [42.0, 33.0]
f.data.sort()
print(f.data)
Gives
[33.0, 42.0]
as expected.