I have a column of dates in column A sorted in ascending order. Cell C1 contains a date. I want a formula to find the earliest date in column A that is equal to or greater than the date in C1.
I realize this can be done by sorting column A in descending order and using the following formula...
=MATCH(C1,A:A,-1)
...but curiosity has me wondering if it's possible without changing the sort order. The formula above returned an error when the worksheet was sorted in ascending order.
Any ideas?
Use this:
=IF(ISNUMBER(MATCH(C1,A:A,0)),MATCH(C1,A:A,0),MATCH(C1,A:A)+1)
It test whether there is an exact match, if so it uses the exact match. Otherwise it uses the default and then moves down one row.
Or simplified:
=MATCH(C1,A:A)+IF(ISNUMBER(MATCH(C1,A:A,0)),0,1)
Or even simpler:
=MATCH(C1,A:A)+ISERROR(MATCH(C1,A:A,0))