Swift - How does one sort an array by internal integer property in the most efficient way

Swift 2.3

Alright folks. Assuming i have a Class named Post, and array of Posts, [Post].

class Posts 
{
  var message : String?
  var scheduledTime : Int?
}
....
var myPosts = [Posts]()...(500 objects)

How can i, in the most efficient/performance wise way(let's assume i have 500 Post objects inside my array), to sort our [Post] array, by our scheduledTime(Int) property?

Was always curious on how to approach this kind of questions. Thanks!

Modern answer (Swift 3 or newer)

Just use sorted(by:) with a closure that compares the first argument's scheduledTime to the second's.

let sortedPosts = myPosts.sorted { $0.scheduledTime < $1.scheduledTime }

Old answer, Swift 2.2

sorted(by:) used to be called sort(_:), but the idea is the same:

let sortedPosts = myPosts.sort { $0.scheduledTime < $1.scheduledTime }