Say I have an array in NumPy containing evaluations of a continuous differentiable function, and I want to find the local minima. There is no noise, so every point whose value is lower than the values of all its neighbors meets my criterion for a local minimum.
I have the following list comprehension which works for a two-dimensional array, ignoring potential minima on the boundaries:
import numpy as N
def local_minima(array2d):
local_minima = [ index
for index in N.ndindex(array2d.shape)
if index[0] > 0
if index[1] > 0
if index[0] < array2d.shape[0] - 1
if index[1] < array2d.shape[1] - 1
if array2d[index] < array2d[index[0] - 1, index[1] - 1]
if array2d[index] < array2d[index[0] - 1, index[1]]
if array2d[index] < array2d[index[0] - 1, index[1] + 1]
if array2d[index] < array2d[index[0], index[1] - 1]
if array2d[index] < array2d[index[0], index[1] + 1]
if array2d[index] < array2d[index[0] + 1, index[1] - 1]
if array2d[index] < array2d[index[0] + 1, index[1]]
if array2d[index] < array2d[index[0] + 1, index[1] + 1]
]
return local_minima
However, this is quite slow. I would also like to get this to work for any number of dimensions. For example, is there an easy way to get all the neighbors of a point in an array of any dimensions? Or am I approaching this problem the wrong way altogether? Should I be using numpy.gradient() instead?
The location of the local minima can be found for an array of arbitrary dimension using Ivan's detect_peaks function, with minor modifications:
import numpy as np
import scipy.ndimage.filters as filters
import scipy.ndimage.morphology as morphology
def detect_local_minima(arr):
# https://stackoverflow.com/questions/3684484/peak-detection-in-a-2d-array/3689710#3689710
"""
Takes an array and detects the troughs using the local maximum filter.
Returns a boolean mask of the troughs (i.e. 1 when
the pixel's value is the neighborhood maximum, 0 otherwise)
"""
# define an connected neighborhood
# http://www.scipy.org/doc/api_docs/SciPy.ndimage.morphology.html#generate_binary_structure
neighborhood = morphology.generate_binary_structure(len(arr.shape),2)
# apply the local minimum filter; all locations of minimum value
# in their neighborhood are set to 1
# http://www.scipy.org/doc/api_docs/SciPy.ndimage.filters.html#minimum_filter
local_min = (filters.minimum_filter(arr, footprint=neighborhood)==arr)
# local_min is a mask that contains the peaks we are
# looking for, but also the background.
# In order to isolate the peaks we must remove the background from the mask.
#
# we create the mask of the background
background = (arr==0)
#
# a little technicality: we must erode the background in order to
# successfully subtract it from local_min, otherwise a line will
# appear along the background border (artifact of the local minimum filter)
# http://www.scipy.org/doc/api_docs/SciPy.ndimage.morphology.html#binary_erosion
eroded_background = morphology.binary_erosion(
background, structure=neighborhood, border_value=1)
#
# we obtain the final mask, containing only peaks,
# by removing the background from the local_min mask
detected_minima = local_min ^ eroded_background
return np.where(detected_minima)
which you can use like this:
arr=np.array([[[0,0,0,-1],[0,0,0,0],[0,0,0,0],[0,0,0,0],[-1,0,0,0]],
[[0,0,0,0],[0,-1,0,0],[0,0,0,0],[0,0,0,-1],[0,0,0,0]]])
local_minima_locations = detect_local_minima(arr)
print(arr)
# [[[ 0 0 0 -1]
# [ 0 0 0 0]
# [ 0 0 0 0]
# [ 0 0 0 0]
# [-1 0 0 0]]
# [[ 0 0 0 0]
# [ 0 -1 0 0]
# [ 0 0 0 0]
# [ 0 0 0 -1]
# [ 0 0 0 0]]]
This says the minima occur at indices [0,0,3], [0,4,0], [1,1,1] and [1,3,3]:
print(local_minima_locations)
# (array([0, 0, 1, 1]), array([0, 4, 1, 3]), array([3, 0, 1, 3]))
print(arr[local_minima_locations])
# [-1 -1 -1 -1]