XPath 3.0: select nodes by condition (find max child nodes by date)

Given XML:

<?xml version="1.0" encoding="UTF-8"?>
<root>
    <c cid="c0" v="100">
        <d did="c00" v="0" dt="2016-01-01" />
        <d did="c01" v="0" dt="2016-02-03" />
        <d did="c02" v="0" dt="2016-01-15" />
    </c>
    <c cid="c1" v="100">
        <d did="c10" v="1" dt="2016-01-01" />
        <d did="c11" v="0" dt="2015-03-03" />
        <d did="c12" v="0" dt="2015-04-15" />
    </c>
</root>

I have to find XPath 2.0 or 3.0, which will return to me list of c nodes by expression: find maximum d node of this c children by dt attribute (parse it as date), and if its v attribute value is "0", return the c node.

I expect to get a one c node (with @cid="c0") as a result, because /root/c[cid="c1"]/d[@dt="2016-01-01"]/@v is not equal to 0 (is equal to 1).

I have stuck on this XPath sofar:

/root/c[d[max(xs:date(@dt))]/@v="0"]

It gives me an error (I'm using Oxygen XML Editor, XPath 3.0):

XPath failed due to: Effective boolean value is not defined for a sequence starting with an atomic value other than a boolean, number, string, or URI

I suppose this is due to misused max function, but cannot get it working.

UPDATES:

1. Lets assume that c nodes will have d children with unique maximum value of their dt attributes.

2. I also tried XPath 3.0 expression:

   /root/c[d[@dt=max(.//@dt/xs:date(.))]/@v="0"]

but it returned me all nodes (wrong result).

Here is a shorter and probably more efficient (the max per a <c> element is calculated just once) XPath 2.0 one-liner:

/*/c[max(d/xs:date(@dt)) = d[@v eq '0']/@dt]

Enjoy!