Our previous implementation for finding distinct elements from a collection used to be :
List<String> names = mongoClient.getDB(dbName).getCollection(collectionName).distinct(NAME_KEY);
Trying to upgrade this into the current implementation with mongo 3.3.0+ as tried is :
List<String> names = mongoClient.getDatabase(dbName)
.getCollection(collectionName, TDocType.class)
.distinct(NAME_KEY, String.class); // compile error - required Class<TResult>
Have also given a try to
.distinct(NAME_KEY, TDocType.class) // doesn't work
What shall be the target type of the iterable in this case?
Edit - The question is not a duplicate of Get distinct records values since the implementation has changed over the upgrade of mongodb-java-driver
.
Improved answer from @jyemin
List<String> list = mongoClient.getDatabase(dbName)
.getCollection(collectionName, TDocType.class)
.distinct(NAME_KEY, String.class)
.into(new ArrayList<>());
Original answer
You can try something like this.
DistinctIterable<String> iterable = mongoClient.getDatabase(dbName).
.getCollection(collectionName, TDocType.class).distinct(NAME_KEY, String.class);
MongoCursor<String> cursor = iterable.iterator();
List<String> list = new ArrayList<>();
while (cursor.hasNext()) {
list.add(cursor.next());
}