im having trouble using multiple operators while programing a simple FizzBuz in C
#include <stdio.h>
int main(void) {
int n;
scanf("%d", &n);
if (0 < n < 10000){
for (int i = 1; i <= n; i ++) {
if (i % 15 == 0) {
puts("TikTak");
}
else if (i % 3 == 0) {
puts("Tik");
}
else if (i % 5 == 0) {
puts("Tak");
}
else {
printf("%d\n", i);
}
}
}else{
printf("-1");
}
}
Now the "if (0 < n < 10000)" comparison operators is ignored for some reason, but if I rewrite it as:
if (n < 10000 && n > 0){
it will work as intended.
Am I missing something? Ill be honest Im newbie in C programing. haha
EDIT: Thanks everybody, haha that was quite simple. I thought that might be the issue I just waned to make surebecause "0 < n < 10000" is litteraly how the assigment says it should look like.
Again, thanks!
Rewrite this condition
if (0 < n < 10000){
like
if (0 < n && n < 10000){
Otherwise the original condition looks like
if (( 0 < n ) < 10000){
and the result of the expression 0 < n is either 1 or 0. So in fact you are comparing 0 or 1 with 10000.
From the C Standard (6.5.8 Relational operators)
6 Each of the operators < (less than), > (greater than), <= (less than or equal to), and >= (greater than or equal to) shall yield 1 if the specified relation is true and 0 if it is false.107) The result has type int.