I have a tree map declared as follows:
TreeMap<Integer, Integer> tree = new TreeMap<Integer, Integer>();
How do I retrieve the key with the maximum value. Is there an O(1) way of achieving this. I know that maximum and minimum keys can be retrieved from a TreeMap in O(1) time as follows:
int maxKey = tree.lastEntry().getKey();
int minKey = tree.firstEntry().getKey();
Thanks for help.
The collection is not sorted by value so the only way is brute force O(n) unless there is another collection with say the reverse map available.
Map<Integer, Integer>map = new TreeMap<>();
int max = map.values().stream().max(Integer::compare).get();