I know how to go through whole array, but I only need number of duplicate occurrences. I'm at beginners level, so just basic use of loops and arrays.
int[] array = {12, 23, -22, 0, 43, 545, -4, -55, 43, 12, 0, -999, -87};
for (int i = 0; i < array.length; i++) {
int count = 0;
for (int j = 0; j < array.length; j++) {
count++;
}
System.out.println(array[i] + "\toccurs\t" + count + "X");
}
You can do better if you use more than just loops and arrays, but a simple algorithm would be to use two nested for
loops, and put an if
statement inside that increments a counter when a duplicate is found.
int[] array = {12, 23, -22, 0, 43, 545, -4, -55, 43, 12, 0, -999, -87};
for (int i = 0; i < array.length - 1; i++) {
int count = 1;
for (int j = i + 1; j < array.length; j++) {
if (array[i] == array[j]) {
count++;
}
}
if (count > 1) {
System.out.println(array[i] + "\toccurs\t" + count + " times");
}
}