[SOLVED] Getopts considers my option chain as the argument for the first one

Getopts considers my option chain as the argument for the first one

The following code is executed in subscript.sh, and subscript.sh is run inside primaryscript.sh

#### primaryscript.sh
#! /bin/bash
#...
"$bss_path"/subscript.sh "$option"
#...

I am using this code to parse my arguments and their values:

#### subscript.sh
#! /bin/bash

while getopts "hw:l:s:b:" opt; do
  case $opt in
    w)
      x="$OPTARG";;
    l)
      xx="$OPTARG";;
    s)
      xxx="$OPTARG";;
    b)
      xxxx="$OPTARG";;
    h)
      print_usage
      exit 0;;  
    \?)
      echo "Invalid option: -$OPTARG"
      exit 1;;
  esac
done

The problem appears when I call my script with multiple arguments:

./myscript -l 5.0.3-0 -s 4.0-0 -b 010

getopts thinks that option l have 5.0.3-0 -s 4.0-0 -b 010 as argument.

What am I doing wrong?

I tried to play around with the : and the option, but as I understood I have to put them behind the options taking an argument right?

And getopts naturally knows that - is the separator for arguments.

$> echo $BASH_VERSION
$> 3.2.25(1)-release

Solution

As Cyrus pointed out in the comment, the problem was how I passed arguments.

./myscript "$options"

The correct way is :

./myscript $options

Since "$options" won't care of the spaces and take the whole string as a single argument.