I want to generate all possible outputs of a list of size N that acts as a 3 digit odometer. For example, if N = 4, I want the following output:
0000 1000 2000 3000 0100 1100 ... 3332 3333.
Here is my code, any help is much appreciated!
odom = [0]*N ## initialize odometer
print odom
while odom[N-1] <= 3:
idx = 1
odom[0] += 1
if odom[0] > 3:
while odom[idx] > 3:
idx += 1
for i in range(idx):
odom[i] = 0
print odom
def foo(n, digits = 4):
if digits == 0:
return ''
msb, lsb = divmod(n, 4)
return str(lsb) + foo(msb, digits - 1)
result = []
number_of_digits = 4
maxn = sum(3 * pow(number_of_digits,n) for n in range(number_of_digits))
for n in range(maxn + 1):
result.append(foo(n, number_of_digits))
result = [foo(n, number_of_digits) for n in range(maxn + 1)]
foo_4 = functools.partial(foo, digits=4)
result = list(map(foo_4, range(maxn + 1)))