#include <stdio.h>
int main(void)
{
int i = 365, j = 100, result = i + j;
printf("i + j is %i\n", result);
int i = 100, j = 1;
printf("i + j is %i\n", result);
return 0;
}
9.c:10:10: error: declaration shadows a local variable [-Werror,-Wshadow] 9.c:8:9: error: redefinition of 'i'
Replace int i = 100
with i = 100
.
You are not allowed to redeclare a variable in the same scope in C and C++. But you can set i
to a different value, which is what my change does.
Finally, if you want the final output of result
to be the sum of the new values of i
and j
, then you have to recompute. Put result = i + j;
just before the printf
call.