Generation of 4 non repeating random numbers using arrays in java

I have this array

int [] marc = new int[4];

i need to insert a set of non repeating random numbers in the range of 1-10 to it

i'm using this for loop to set random numbers

for (he = 0; he < 4; he++) {
    marc[he] = rn.nextInt(10 - 1 + 1) + 1;
    marc[he]++; 
}

it gives me random numbers but repeated ones inside the array

i'm also using

java.util.Random;

Well, yes, numbers can be repeated while being random. You need to do your own logic to validate if they're already on the array, this can be done with the following code:

In the code I used an array of 10 elements to observe there aren't repeated numbers even on that situation.

import java.util.Random;

public class RandomNumbersNoRepeating {
    public static void main(String[] args) {
        int array[] = new int[10];
        Random random = new Random();

        //Fills the array
        for (int i = 0; i < array.length; i++) {
            boolean found = false;
            int r = 0;
            do {
                found = false;
                r = random.nextInt(10) + 1;
                //Here we check if the number is not on the array yet
                for (int j = 0; j < array.length; j++) {
                    if (array[j] == r) {
                        found = true;
                        break;
                    }
                }
            } while (found);

            array[i] = r;
        }

        //Prints the array
        for (int i = 0; i < array.length; i++) {
            System.out.println(array[i]);
        }
    }
}

Another possible solution, as given in a comment could be to shuffle an array from 1-10, and get the first four numbers