I've been trying to use boost::bind to post a call to a member function onto an io_strand but have been getting errors. I have manged to create a simplistic equivalent example of what I am trying to do and have seen the same error in the following context:
I have the following class containing the doThings() member function I want to call:
class base
{
public:
int x = 1;
template<typename B>
void doThings(B&& b)
{}
};
There is then a subclass of this (to accurately represent the scenario I am encountering my error - I don't think it makes a difference)
class child : public base
{
int y = 2;
};
I have the following code trying to make the boost::bind call:
template<typename A>
void getInt(child c, A&& a)
{
boost::bind((void(child::*)(A)) &child::doThings, &c, std::forward<A>(a))();
}
And then this is being called as follows:
int main()
{
child c = child();
getInt(c, 7);
}
When I compile the above code I get the following error:
error: no matches converting function ‘doThings’ to type ‘void (class child::*)(int)’
If I change the function signature of doThings() to take a regular B type rather than a universal reference i.e.
B
rather than B&&
then it compiles a runs with no issues.
I suspect my issue is something to with the cast I'm doing in getInt():
(void(child::*)(A))
But I don't know what I would need to change it to. A&&
wouldn't work in this context as I believe it would represent an r-value reference in that context. The compilation error I get when I try it seems to confirm this:
error: cannot bind ‘int’ lvalue to ‘int&&’
For completeness: if I don't attempt to perform a cast then I get the following compilation error:
error: no matching function for call to ‘bind(unresolved overloaded function type, child*, int)’
Could someone please enlighten me on what I would need to do in order to make my boost::bind call valid in this scenario please?
I am using C++11
I would suggest against using boost::bind
, as lambda expressions can be used to cleanly bind arguments (avoiding many pitfalls of bind
explained in this talk by STL).
I'm assuming that you want to:
Capture a
by move if an rvalue-reference is passed to getInt
.
Capture a
by reference if an lvalue-reference is passed to getInt
.
I'm also assuming that:
A
is not int
in your real code, otherwise perfect-forwarding would not make sense.
You want to avoid unnecessary copies of a
or that A
could be a move-only type.
You only have access to C++11 (and not to newer standards).
If you need to "perfectly-capture" a
(i.e. capture-by-move if A
is an rvalue-reference, capture-by-reference if A
is an lvalue-reference), you need some sort of wrapper.
Unfortunately this is non-trivial, even though it gets better in C++14 and C++17. Here's an example of how the final syntax could look:
template<typename A>
void getInt(child c, A&& a)
{
// `a_wrapper` stores an `A&` or an `A` depending on the value category
// of `a`. Copying it should not copy `a` - it should conditionally move
// it depending on the original value category of `a`.
auto a_wrapper = forward_capture_wrapper(std::forward<A>(a));
// `forward_like` retains information about `a`'s value category so that
// it can be used in the body of the lambda to forward the reference/value
// stored inside `a_wrapper`.
// vvvvvvvvvvvvvvv
[&a, a_wrapper]{ c.doThings(forward_like<A>(a_wrapper.get()); }();
// ^^^^^^^^^^^^^^^
// `a_wrapper.get()` returns a reference that can then be moved or passed
// to `c.doThings`.
}
As you can see, you need a template function called forward_capture_wrapper
that deals with "perfect-capture". You can find information on how to implement that in these resources:
"Move capture in lambda" - covers how to implement capture-by-move in C++11. This is trivial in C++14 thanks to generalized lambda captures.
"capturing perfectly-forwarded objects in lambdas" - this is an article I've written that covers how to implement "perfect capture" in C++14/17. It's a good starting point to understand the issue of "perfect capture" and it should be possible to convert the code to something C++11 compliant.
"Capturing perfectly-forwarded variable in lambda" - this StackOverflow question I asked some time ago covers some ways of implementing "perfect capture" in C++14.
By combining the resources above you should be able to implement a "perfect capture wrapper" in C++11.
You also need a forward_like
helper function that preserves the original value category of the a
argument. You can find an implementation of that: