Function Prototypes with multi-dimensional arrays as a parameter

Brand new to C, I come from a Java background.

I am having an issue where I can't compile because the compiler wants to know at compile time the size of my array. For example, I want to print my array to the console. It won't allow me to declare a function prototype as such:

void printRoom(char[][], int, int); //not allowed 

What am I supposed to do instead? Is there not a way around this? Online resources that I have found seem to indicate that I MUST know the dimensions if I want to use a function prototype. It appears that it also requires that the function header have the size of the array as well.

void printRoom(char room[][], int height, int width){ // not allowed, missing array bounds

Would a valid solution to this problem just be to say the array is of size 1000*1000 (the maximum array size I can expect)? That seems sloppy to me but I'm pretty sure it would work as long as I stayed within the bounds of what the array size is actually supposed to be.

I am NOT interested in pointers and malloc at this time.

If the compiler supports variable length arrays then you can declare the function the following way

void printRoom( int, int, char[*][*]); 

or just

void printRoom( int, int, char[][*]); 

Here is a demonstrative program

#include <stdio.h>
#include <string.h>

void printRoom( int, int, char[*][*]); 

void printRoom( int m, int n, char a[m][n] )
{
    for ( int i = 0; i < m; i++ )
    {
        printf( "%3s ", a[i] );
        putchar( ' ');
    }
    printf( "\n" );
}   

int main(void) 
{
    const int M = 2;
    const int N = 10;
    char a[M][N];

    strcpy( a[0], "Hello" ),
    strcpy( a[1], "World" );

    printRoom( M, N, a );

    return 0;
}

Its output is

Hello  World 

If the compiler does not support VLAs then the number of columns has to be a constant. For example

#define N 100

//...

void printRoom(char[][N], int, int);