Having the following snippet:
#!/usr/bin/env python
from scapy.layers.inet import UDP, IP
from scapy.layers.dns import DNS, DNSQR
from scapy.sendrecv import sr1
dns_resp = sr1(IP(dst="8.8.8.8") / UDP(dport=53) /
DNS(rd=1, qd=DNSQR(qname="www.stackoverflow.com")))
print dns_resp.summary()
print dns_resp
I get the following result:
Begin emission:
.Finished to send 1 packets.
*
Received 2 packets, got 1 answers, remaining 0 packets
IP / UDP / DNS Ans "stackoverflow.com."
E��/
stackoverflowcom
���eE��eAE��e�E��e�E
I can remove www. from the URL and then I will get the IP but I cannot programmatically extract it from the package (in code).
Begin emission:
.Finished to send 1 packets.
*
Received 2 packets, got 1 answers, remaining 0 packets
IP / UDP / DNS Ans "151.101.1.69"
stackoverflowcom
�eE
�eAE
�e�E
�e�E
I would like to resolve www.stackoverflow.com into it's IP address. How can I do it regardless of the input? (whether it's www.stackoverflow.com or stackoverflow.com)
I tried doing this in scapy's console and I get the following:
>> r=sr1(IP(dst="8.8.8.8")/UDP(dport=53)/DNS(rd=1,qd=DNSQR(qname="www.stackoverflow.com")))
Begin emission:
.Finished to send 1 packets.
.*
Received 3 packets, got 1 answers, remaining 0 packets
>>> r
<IP version=4L ihl=5L tos=0x0 len=145 id=7835 flags= frag=0L ttl=47 proto=udp chksum=0x9a88 src=8.8.8.8 dst=192.168.1.129 options=[] |<UDP sport=domain dport=domain len=125 chksum=0x738c |<DNS id=0 qr=1L opcode=QUERY aa=0L tc=0L rd=1L ra=1L z=0L ad=0L cd=0L rcode=ok qdcount=1 ancount=5 nscount=0 arcount=0 qd=<DNSQR qname='www.stackoverflow.com.' qtype=A qclass=IN |> an=<DNSRR rrname='www.stackoverflow.com.' type=CNAME rclass=IN ttl=2927 rdata='stackoverflow.com.' |<DNSRR rrname='stackoverflow.com.' type=A rclass=IN ttl=263 rdata='151.101.1.69' |<DNSRR rrname='stackoverflow.com.' type=A rclass=IN ttl=263 rdata='151.101.65.69' |<DNSRR rrname='stackoverflow.com.' type=A rclass=IN ttl=263 rdata='151.101.129.69' |<DNSRR rrname='stackoverflow.com.' type=A rclass=IN ttl=263 rdata='151.101.193.69' |>>>>> ns=None ar=None |>>>
Can I somehow filter this information by dns response type ( A type response is of type 1 in scapy as far as I know)
You can use dns_resp[DNS] to access layer DNS and it has some functions to get details.
print "--------------------"
print dns_resp.summary()
print "--------------------"
#print 'name:', dns_resp.payload.payload.name
print 'name:', dns_resp[DNS].name
#print repr(dns_resp.payload.payload)
print repr(dns_resp[DNS])
print "--------------------"
#print 'layers:', dns_resp.payload.payload.ancount
print 'layers:', dns_resp[DNS].ancount
print "--------------------"
for x in range(dns_resp[DNS].ancount):
print dns_resp[DNSRR][x].rdata
print "--------------------"
Result
--------------------
IP / UDP / DNS Ans "stackoverflow.com."
--------------------
name: DNS
<DNS id=0 qr=1L opcode=QUERY aa=0L tc=0L rd=1L ra=1L z=0L ad=0L cd=0L rcode=ok qdcount=1 ancount=5 nscount=0 arcount=0 qd=<DNSQR qname='www.stackoverflow.com.' qtype=A qclass=IN |> an=<DNSRR rrname='www.stackoverflow.com.' type=CNAME rclass=IN ttl=3379 rdata='stackoverflow.com.' |<DNSRR rrname='stackoverflow.com.' type=A rclass=IN ttl=79 rdata='151.101.1.69' |<DNSRR rrname='stackoverflow.com.' type=A rclass=IN ttl=79 rdata='151.101.65.69' |<DNSRR rrname='stackoverflow.com.' type=A rclass=IN ttl=79 rdata='151.101.129.69' |<DNSRR rrname='stackoverflow.com.' type=A rclass=IN ttl=79 rdata='151.101.193.69' |>>>>> ns=None ar=None |>
--------------------
layers: 5
--------------------
stackoverflow.com.
151.101.1.69
151.101.65.69
151.101.129.69
151.101.193.69
--------------------
I found information on page which was removed so I put link to Archive.org
Original: Scapy – Iterating over DNS Responses
Archive.org: Scapy – Iterating over DNS Responses