I tried to optimize my code using macro, but it doesn't compile in some sentences. For simplification, I writed codes below to describe what I want to work out:
#define MACRO(x, y) ((x) + (y))
#define X 2,3
int fun(x, y)
{
return x+y;
}
int main(void)
{
int res;
res = fun(X); //ok
res = MACRO(X); //**error:macro "MACRO" requires 2 arguments, but only 1 given**
printf("%d\n", res);
return 0;
}
I used to believe that macros simply replace words so it's no problem to do this, but now I think I was wrong. :(
More accurately: I was tring to do something like:
//global.h
#define MACRO(brief, num) fun(__LINE__, brief, num)
//test.c
#include <global.h>
#define X "brief",3
void fun(int line_num, char* brief, int num)
{
printf("%d, %s,%d\n", line_num, brief, num); //do something
}
int main(void)
{
fun(__LINE__, X); //ok
MACRO("brief",3); //ok
MACRO(X); //error: macro "MACRO" requires 2 arguments, but only 1 given
return 0;
}
So I need to use this type of macro to reduce args.
I searched everywhere yesterday but nothing was found, I hope I could receive answers here.
You can use the variable arguments facility of the preprocessor, as in the following example (available on IdeOne):
#include <stdio.h>
#define MACRO(...) MACRO_IMPLEMENTATION(__VA_ARGS__)
#define MACRO_IMPLEMENTATION(x,y) ((x)+(y))
#define X 2,3
int main (void) {
printf ("MACRO (X) = %d\n", MACRO (X));
printf ("MACRO (2,3) = %d\n", MACRO (2,3));
return 0;
}
The output is
MACRO (X) = 5
MACRO (2,3) = 5
The definition of MACRO
takes a variable number or arguments, which are bound to __VA_ARGS__
(see section 6.10.3 in the standard). The definition of MACRO
calls MACRO_IMPLEMENTATION
which now sees two arguments either because MACRO
was called with two or because it was called with an argument which expands to a list of two arguments.