I made an iOS app with Xcode and Swift.
I want to open specific hyperlinks in Safari browser, there others in the WebView itself.
To reach this, I'll have to check when an hyperlinks gets clicked.
This is the code I have so far:
//
// PushViewController.swift
// App
//
//
import UIKit
class PushViewController: UIViewController, UIWebViewDelegate {
@IBOutlet var openpushmessage: UIWebView!
var weburl:String = "http://www.example.com"
override func viewDidLoad() {
super.viewDidLoad()
let url: NSURL = NSURL(string: weburl)!
let requestURL: NSURLRequest = NSURLRequest(URL: url)
openpushmessage.loadRequest(requestURL)
}
override func webView(_ webView: UIWebView, shouldStartLoadWithRequest request: URLRequest, navigationType: UIWebViewNavigationType) -> Bool {
if navigationType == .linkClicked
{
print("You clicked a hypelink!")
}
return true
}
}
The code in viewDidLoad()
opens the loads the main URL (http://www.example.com) from my server. That works fine.
override fun webView[…]
should detect if a hyperlink is clicked and then print("You clicked a hypelink!")
.
But unfortunately I'm getting the following errors:
What am I doing wrong? How to get rid of these errors?
This is the working solution (Xcode 7.3.1 and Swift 2.2):
func webView(webView: UIWebView, shouldStartLoadWithRequest request: NSURLRequest, navigationType: UIWebViewNavigationType) -> Bool {
if request.URL?.query?.rangeOfString("target=external") != nil {
if let url = request.URL {
UIApplication.sharedApplication().openURL(url)
return false
}
}
return true
}
Many thanks to danhhgl from freelancer.com!