typescripttypescript1.8

Obtaining the return type of a function

I have the following function:

function test(): number {
    return 42;
}

I can obtain the type of the function by using typeof:

type t = typeof test;

Here, t will be () => number.

Is there a way to obtain the return type of the function? I would like t to be number instead of () => number.

Solution

  • EDIT

    As of TypeScript 2.8 this is officially possible with ReturnType<T>.

    type T10 = ReturnType<() => string>;  // string
type T11 = ReturnType<(s: string) => void>;  // void
type T12 = ReturnType<(<T>() => T)>;  // {}
type T13 = ReturnType<(<T extends U, U extends number[]>() => T)>;  // number[]

    See this pull request to Microsoft/TypeScript for details.

    TypeScript is awesome!

    Old-school hack

    Ryan's answer doesn't work anymore, unfortunately. But I have modified it with a hack which I am unreasonably happy about. Behold:

    const fnReturnType = (false as true) && fn();

    It works by casting false to the literal value of true, so that the type system thinks the return value is the type of the function, but when you actually run the code, it short circuits on false.