Is it possible to get classification report from cross_val_score through some workaround? I'm using nested cross-validation and I can get various scores here for a model, however, I would like to see the classification report of the outer loop. Any recommendations?
# Choose cross-validation techniques for the inner and outer loops,
# independently of the dataset.
# E.g "LabelKFold", "LeaveOneOut", "LeaveOneLabelOut", etc.
inner_cv = KFold(n_splits=4, shuffle=True, random_state=i)
outer_cv = KFold(n_splits=4, shuffle=True, random_state=i)
# Non_nested parameter search and scoring
clf = GridSearchCV(estimator=svr, param_grid=p_grid, cv=inner_cv)
# Nested CV with parameter optimization
nested_score = cross_val_score(clf, X=X_iris, y=y_iris, cv=outer_cv)
I would like to see a classification report here along side the score values. http://scikit-learn.org/stable/modules/generated/sklearn.metrics.classification_report.html
We can define our own scoring function as below:
from sklearn.metrics import classification_report, accuracy_score, make_scorer
def classification_report_with_accuracy_score(y_true, y_pred):
print classification_report(y_true, y_pred) # print classification report
return accuracy_score(y_true, y_pred) # return accuracy score
Now, just call cross_val_score
with our new scoring function, using make_scorer
:
# Nested CV with parameter optimization
nested_score = cross_val_score(clf, X=X_iris, y=y_iris, cv=outer_cv, \
scoring=make_scorer(classification_report_with_accuracy_score))
print nested_score
It will print the classification report as text at the same time return the nested_score
as a number.
http://scikit-learn.org/stable/auto_examples/model_selection/plot_nested_cross_validation_iris.html example when run with this new scoring function, the last few lines of the output will be as follows:
# precision recall f1-score support
#0 1.00 1.00 1.00 14
#1 1.00 1.00 1.00 14
#2 1.00 1.00 1.00 9
#avg / total 1.00 1.00 1.00 37
#[ 0.94736842 1. 0.97297297 1. ]
#Average difference of 0.007742 with std. dev. of 0.007688.