C code gives wrong answer but java code gives correct answer on spoj

I am solving following problem on SPOJ.It is simple insertion sort algorithm. My java code works but C code is giving wrong answer. what wrong i am doing?

Please help and thanks lot......:)

link of problem statement

java code

public class Main {

   public static void main(String[] args) throws NumberFormatException, IOException {
      BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
      int t = Integer.parseInt(br.readLine());
      while (t > 0) {
         int n = Integer.parseInt(br.readLine());
         String str = br.readLine();
         String arr[] = str.split(" ");
         int inputArr[] = new int[n];
         for (int i = 0; i < n; i++) {
            inputArr[i] = Integer.parseInt(arr[i]);
         }
         int key = 0;
         int count = 0;
         for( int i = 1; i < n; i++ ) {
            key = inputArr[i];
            int j = i - 1;
            while (j >= 0 && inputArr[j] > key) {
               inputArr[j + 1] = inputArr[j];
               j = j - 1;
               count++;
            }
            inputArr[j + 1] = key;
         }
         System.out.println(count);
         t--;
      }
   }
}

C code

#include<stdio.h>
int main() {
   int t=0;
   scanf("%d",&t);
   while( t > 0 ) {
      int n=0;
      scanf("%d",&n);
      int arr[n];
      int key=0;
      for(int i=0; i<n; i++) {
         scanf("%d",&arr[i]);
      }
      int count=0;
      int j=0;
      for(int i=1; i<n; i++) {
         key = arr[i];
         j   = i - 1;
         while(j>=0&&arr[j]>key) {
            arr[j+1]=arr[j];
            count++;
            j = j-1;
         }
         arr[j+1]=key;
      }
      printf("%d",count);
      t--;
   }
   return 0;
}

The code itself is correct, but your output is wrong. Expected output format is a number followed by newline. Your Java code uses println which automatically inserts newline. Your C code lacks \n. printf("%d\n", count); is what you should use.