I have written simple rest API that will add music track data to mongodb.
I am able to write track successfully, however I would like to handle error case.
My code as below -
def saveTrack = Action.async(parse.json) {
import model.Track.trackFormat
implicit request =>
request.body.validate[Track].map { data =>
trackService.save(data).onComplete {
case Success(value) => Ok(Json.obj("message" -> Messages("track.save.ack")))
case Failure(e) => Ok(Json.obj("message" -> Messages("track.save.nack")))
}
}
Future.successful(Ok(Json.obj("message" -> Messages("track.save.fin"))))
}
Lets suppose there is some failure happen in trackService.save(data) then I want to return error code. I am wondering how to achieve that.
Thanks Pari
def saveTrack = Action.async(parse.json) { implicit request =>
request
.body
.validate[Track]
.map { data =>
trackService.save(data).map { v =>
Ok(Json.toJson(Json.obj("message" -> Messages("ack"))))
}.recover {
case _ =>
Ok(Json.toJson(Json.obj("message" -> Messages("nack"))))
}
}.getOrElse {Future.successful(BadRequest(Json.obj("error" -> "bad json")))
}
}
Use recover
to handle errors and getOrElse
in case the json body is not matching your model.