I tried to set up a property so that the value of a variable is change a function will be called:
The DataExchange class:
#ifndef DATAEXCHANGE_H
#define DATAEXCHANGE_H
#include <QObject>
#include <QDebug>
class DataExchange : public QObject
{
Q_OBJECT
Q_PROPERTY(bool serialOn READ get_serialOn WRITE set_serialOn NOTIFY serialOnChanged)
public:
DataExchange(QObject *parent = 0);
~DataExchange();
bool get_serialOn() const
{
return _serialOn;
}
void set_serialOn(bool value)
{
if (value != _serialOn)
{
_serialOn = value;
emit serialOnChanged(_serialOn);
}
}
signals:
void serialOnChanged(bool);
private:
bool _serialOn;
};
#endif // DATAEXCHANGE_H
DataExchange.cpp
DataExchange::DataExchange(QObject *parent) :
QObject(parent)
{}
DataExchange::~DataExchange() { }
MainFrame:
class MainWindow : public QMainWindow
{
Q_OBJECT
public:
explicit MainWindow(QWidget *parent = 0);
~MainWindow();
...
DataExchange *deHandle;
};
MainWindow::MainWindow(QWidget *parent) :
QMainWindow(parent),
ui(new Ui::MainWindow)
{
ui->setupUi(this);
removeToolBar(ui->mainToolBar);
deHandle = new DataExchange;
}
But it gives the error:
error: linker command failed with exit code 1 (use -v to see invocation)
Where does this error come from and how to solve it?
I have uploaded the code that is similar to yours but I have no problems: github.com/eyllanesc/stackoverflow/tree/master/Test – eyllanesc
This one is a good example. But after changes were made, need to: clean project -> run qmake -> ...
Then it will finally work.
Previously I only cleaned project and rebuilt project, which somehow didn't solve problem.