I'm trying to accessing an API that has json input with multi dimensional, this is the array
[{
"Value 1":"a",
"Value 2":
{
"Value 3":
{
"Value4":11,
"Value5":"C",
},
"Value 4":
{
"Value6":12,
}
}
}]
I want to echo the "11" in Value4 and "12" in Value6. I've try to echo it
$varkota = 'url to json output';
$datakota = json_decode(file_get_contents($varkota, true));
$data1 = json_decode($datakota[0]->Value2);
$data2 = json_decode($data1[0]->Value3);
echo $data2[0]->Value4;
error told me:
! ) SCREAM: Error suppression ignored for
( ! ) Warning: json_decode() expects parameter 1 to be string, object given in debug.php on line 6
Call Stack
# Time Memory Function Location
1 0.0020 145280 {main}( ) ..\debug.php:0
2 4.1329 188648 json_decode ( ) ..\debug.php:6
( ! ) SCREAM: Error suppression ignored for
( ! ) Notice: Trying to get property of non-object in debug.php on line 7
Call Stack
# Time Memory Function Location
1 0.0020 145280 {main}( ) ..\debug.php:0
( ! ) SCREAM: Error suppression ignored for
( ! ) Notice: Trying to get property of non-object in on line 8
Call Stack
# Time Memory Function Location
1 0.0020 145280 {main}( ) ..\debug.php:0
Any idea?
Firstly, you need to use json_decode only once, and your keys are having spaces and the keys which are having spaces then you need to enclose it as string and in {}. Try it like,
$datakota = json_decode(file_get_contents($varkota, true));
$data1 = $datakota[0]->{'Value 2'};
$data2 = $data1->{'Value 3'}; // no need to use array [0], as Value 2 is object
echo $data2->Value4; // no need to use array [0], as Value 3 is also an object
In a single line, just use it as
echo $datakota[0]->{'Value 2'}->{'Value 3'}->Value4;