Using the Python Enum class, is there a way to test if an Enum contains a specific int value without using try/catch?

With the following class:

from enum import Enum

class Fruit(Enum):
    Apple = 4
    Orange = 5
    Pear = 6

How can I test for the value 6 (returning true), or the value 7 (returning false)?

UPDATE

my answer is outdated. for newer python versions see Filip Poplewski's answer.

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test for values

variant 1

note that an Enum has a member called _value2member_map_ (which is undocumented and may be changed/removed in future python versions):

print(Fruit._value2member_map_)
# {4: <Fruit.Apple: 4>, 5: <Fruit.Orange: 5>, 6: <Fruit.Pear: 6>}

you can test if a value is in your Enum against this map:

5 in Fruit._value2member_map_  # True
7 in Fruit._value2member_map_  # False

variant 2

if you do not want to rely on this feature this is an alternative:

values = [item.value for item in Fruit]  # [4, 5, 6]

or (probably better): use a set; the in operator will be more efficient:

values = set(item.value for item in Fruit)  # {4, 5, 6}

then test with

5 in values  # True
7 in values  # False

add has_value to your class

you could then add this as a method to your class:

class Fruit(Enum):
    Apple = 4
    Orange = 5
    Pear = 6

    @classmethod
    def has_value(cls, value):
        return value in cls._value2member_map_ 

print(Fruit.has_value(5))  # True
print(Fruit.has_value(7))  # False

starting form python 3.9 (?) python offers IntEnum. with these you could do this:

from enum import IntEnum

class Fruit(IntEnum):
    Apple = 4
    Orange = 5
    Pear = 6

print(6 in iter(Fruit))  # True

note there is no need to create a list; just iterating over iter(Fruit) will do. again, if this is needed repeatedly it may be worth creating a set as above:

values = set(Fruit)
print(5 in values)  # True

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test for keys

if you want to test for the names (and not the values) i would use _member_names_:

'Apple' in Fruit._member_names_  # True
'Mango' in Fruit._member_names_  # False