In my previous question I asked how to read from a memory just as from a file. Because my whole file was in memory I wanted to read it similarly.
I found answer to my question but actually I need to read lines as a wstring
. With file I can do this:
wifstream file;
wstring line2;
file.open("C:\\Users\\Mariusz\\Desktop\\zasoby.txt");
if(file.is_open())
{
while(file.good())
{
getline(file,line2);
wcout << line2 << endl;
}
}
file.close();
Even if the file is in ASCII.
Right now I'm simply changing my string
line to wstring
with a function from this answer. However, I think if there is a way to treat this chunk of memory just like a wistream
it would be a faster solution to get this lines as wstring
s. And I need this to be fast.
So anybody know how to treat this chunk of memory as a wistream
?
I assume that your data is already converted into the desired encoding (see @detunized answer).
Using my answer to your previous question the conversion is straight forward:
namespace io = boost::iostreams;
io::filtering_wistream in;
in.push(warray_source(array, arraySize));
If you insist on not using boost then the conversion goes as follows (still straight forward):
class membuf : public wstreambuf // <- !!!HERE!!!
{
public:
membuf(wchar_t* p, size_t n) { // <- !!!HERE!!!
setg(p, p, p + n);
}
};
int main()
{
wchar_t buffer[] = L"Hello World!\nThis is next line\nThe last line";
membuf mb(buffer, sizeof(buffer)/sizeof(buffer[0]));
wistream istr(&mb);
wstring line;
while(getline(istr, line))
{
wcout << L"line:[" << line << L"]" << endl;
}
}
Also consider this for why use plain char
UTF-8 streams.