In defining variable of a list object, for example:
x = [1,2,0.2,3,4]
y = x
x.sort()
I would expect that y
is still equal to [1, 2, 0.2, 3, 4]
, but it does not. The value of y
changed as x
changed. To counter this, I found that using y = x.copy()
can preserve the value in the first line.
On the other hand, another example :
x = 5
y = x
x = 4
from this the value of y
is still 5
, it does not change as x
change.
My question : is this due to the design in list's class, or there is another explanation? I found the dynamic change also happen when using x.append(value)
. Any insight is appreciated. Regards, Arief
Every variable is just a pointer to an Python object, if you have two variables pointing to the same object then you'll see the changes in each of them (and .sort
works in-place, if you want a new list
you should use x = sorted(x)
). However if you re-assign a variable then it will point to a different object.
I included some images to better visualize what's happening (not high-quality but I hope it conveys the message).
x = [1,2,0.2,3,4]
y = x
If you copy
(it's a shallow copy so the list-contents still refer to the same items!):
x = [1,2,0.2,3,4]
y = x.copy()
Your second case is just the same:
x = 5
y = x
But then you re-assign the variable x
(so it points to another object thereafter):
x = 4