What am I doing wrong here? I am getting this error on:
SELECT LEFT(SUBSTRING(batchinfo.datapath, PATINDEX('%[0-9][0-9][0-9]%', batchinfo.datapath), 8000),
PATINDEX('%[^0-9]%', SUBSTRING(batchinfo.datapath, PATINDEX('%[0-9][0-9][0-9]%',
batchinfo.datapath), 8000))-1),
qvalues.name,
qvalues.compound,
qvalues.rid
FROM batchinfo JOIN qvalues ON batchinfo.rowid=qvalues.rowid
WHERE LEN(datapath)>4
GROUP BY 1,2,3
HAVING rid!=MAX(rid)
I would like to group by the first, second, and third columns having the max rid.
It works fine without the group by and having.
To start with you can't do this:
having rid!=MAX(rid)
The HAVING clause can only contain things which are attributes of the aggregate groups.
In addition, 1, 2, 3 is not valid in GROUP BY in SQL Server - I think that's only valid in ORDER BY.
Can you explain why this isn't what you are looking for:
select
LEFT(SUBSTRING(batchinfo.datapath, PATINDEX('%[0-9][0-9][0-9]%', batchinfo.datapath), 8000), PATINDEX('%[^0-9]%', SUBSTRING(batchinfo.datapath, PATINDEX('%[0-9][0-9][0-9]%', batchinfo.datapath), 8000))-1),
qvalues.name,
qvalues.compound,
MAX(qvalues.rid)
from batchinfo join qvalues on batchinfo.rowid=qvalues.rowid
where LEN(datapath)>4
group by LEFT(SUBSTRING(batchinfo.datapath, PATINDEX('%[0-9][0-9][0-9]%', batchinfo.datapath), 8000), PATINDEX('%[^0-9]%', SUBSTRING(batchinfo.datapath, PATINDEX('%[0-9][0-9][0-9]%', batchinfo.datapath), 8000))-1),
qvalues.name,
qvalues.compound