How to gulp-regex-replace only the first match?

Below is the content from project.json file. I want the first occurrence of 'version' value to be replaced.

{
  "title": "Project Title",
  "copyright": "Copyright Info",
  "description": "Project Description",
  "version": "1.0.0",
  "buildOptions": {
    "xmlDoc": true
  },
  "dependencies": {
    "Microsoft.NETCore.App": {
      "version": "1.0.1",
      "type": "platform"
    }
  }
}

The below code using gulp-regex-replace changes all occurrences of version value to 1.0.1.

var targetVersion= "1.0.1";
gulp.task('replace', function () {
    return gulp.src(['./src/**/project.json'])
        .pipe(bom())
        .pipe(replace({ regex: '\\n\\s\\s\\"version\\"\\:\\s\\"([0-9a-zA-Z.-]+)\\"', replace: `${targetVersion}` }))
        .pipe(gulp.dest('./src'));
});

How can I make this code replace only the first occurrence of version value?

The gulp-regex-replace plugin uses global match: https://github.com/mikrofusion/gulp-regex-replace/blob/master/index.js#L31

Another similar plugin gulp-replace accepts a custom regexp object:

replace(/__your_pattern__/, targetVersion);

Without the g modifier in the pattern, JS will only match the first occurrence.