[SOLVED] How to print all lemma_names of word without repeating its synonyms and pos

How to print all lemma_names of word without repeating its synonyms and pos_tag more than once in NLTK synsets?

I'm trying to find a synsets of words. Here's my codes:

from nltk.corpus import wordnet as wn
from nltk import pos_tag

def getSynonyms(word1):
    synonymList1 = []
    for data1 in word1:
        wordnetSynset1 = wn.synsets(data1)
        tempList1=[]
        for synset1 in wordnetSynset1:
            synLemmas = synset1.lemma_names()
            for i in xrange(len(synLemmas)):
                word = synLemmas[i].replace('_',' ')
                tempList1.append(pos_tag(word.split()))
        synonymList1.append(tempList1)
    return synonymList1

word1 = ['study']

syn1 = getSynonyms(word1)

print syn1

and here's the output :

[[[(u'survey', 'NN')], [(u'study', 'NN')], [(u'study', 'NN')], [(u'work', 'NN')], [(u'report', 'NN')], [(u'study', 'NN')], [(u'written', 'VBN'), (u'report', 'NN')], [(u'study', 'NN')], [(u'study', 'NN')], [(u'discipline', 'NN')], [(u'subject', 'NN')], [(u'subject', 'JJ'), (u'area', 'NN')], [(u'subject', 'JJ'), (u'field', 'NN')], [(u'field', 'NN')], [(u'field', 'NN'), (u'of', 'IN'), (u'study', 'NN')], [(u'study', 'NN')], [(u'bailiwick', 'NN')], [(u'sketch', 'NN')], [(u'study', 'NN')], [(u'cogitation', 'NN')], [(u'study', 'NN')], [(u'study', 'NN')], [(u'study', 'NN')], [(u'analyze', 'NN')], [(u'analyse', 'NN')], [(u'study', 'NN')], [(u'examine', 'NN')], [(u'canvass', 'NN')], [(u'canvas', 'NN')], [(u'study', 'NN')], [(u'study', 'NN')], [(u'consider', 'VB')], [(u'learn', 'NN')], [(u'study', 'NN')], [(u'read', 'NN')], [(u'take', 'VB')], [(u'study', 'NN')], [(u'hit', 'VB'), (u'the', 'DT'), (u'books', 'NNS')], [(u'study', 'NN')], [(u'meditate', 'NN')], [(u'contemplate', 'NN')]]]

as we can see, 'study','NN' appears more than once

how to print only once for each synonyms without repitition?

so each synonyms represented with only one synonym

Solution

Instead of always appending to the list you have inside the for loop, in the line tempList1.append(pos_tag(word.split())). You should check if the element you are trying to add is there in the list already. Having a simple if statement check should do it.

if pos_tag(word.split()) not in tempList1:
   tempList1.append(pos_tag(word.split()))

This was an element will not be added twice.