I have a pattern string with a wild card say X (E.g.: abc*).
Also I have a set of strings which I have to match against the given pattern.
E.g.:
abf - false
abc_fgh - true
abcgafa - true
fgabcafa - false
I tried using regex for the same, it didn't work.
Here is my code
String pattern = "abc*";
String str = "abcdef";
Pattern regex = Pattern.compile(pattern);
return regex.matcher(str).matches();
This returns false
Is there any other way to make this work?
Thanks
Just use bash style pattern to Java style pattern converter:
public static void main(String[] args) {
String patternString = createRegexFromGlob("abc*");
List<String> list = Arrays.asList("abf", "abc_fgh", "abcgafa", "fgabcafa");
list.forEach(it -> System.out.println(it.matches(patternString)));
}
private static String createRegexFromGlob(String glob) {
StringBuilder out = new StringBuilder("^");
for(int i = 0; i < glob.length(); ++i) {
final char c = glob.charAt(i);
switch(c) {
case '*': out.append(".*"); break;
case '?': out.append('.'); break;
case '.': out.append("\\."); break;
case '\\': out.append("\\\\"); break;
default: out.append(c);
}
}
out.append('$');
return out.toString();
}
Is there an equivalent of java.util.regex for “glob” type patterns?
Convert wildcard to a regex expression