Am doing WordXml parsar using JAVA.

And now i want to check (F(1) = 44) this type of pattern will be occured or not in a paragraph.

Note: Inside of open close will have must integer value.

Folloing pattern i will need to check.

(text text (text) text)
(F(1) = 44)
(text text [text] text)
[text text (text) text]

But, Clearly don't know how to make regex pattern for above the senarios.

So, Please suggest me. And anybody pls let me know.

You can use this regex \([a-zA-Z]+\(\d+\)\s*=\s*\d+\), which mean

• one or more alphabetic [a-zA-Z]+
• followed by one or more degit between parentheses \(\d+\)
• followed by one or more space \s*
• followed then by equal =
• followed then by one or more space \s*
• followed then by one or more degit \d+
• all this between parentheses \([a-zA-Z]+\(\d+\)\s*=\s*\d+\)

with Pattern like this :

String[] texts = new String[]{"(text text (text) text)",
    "(F(1) = 44)",
    "(text text [text] text)",
    "[text text (text) text]"};
String regex = "\\([a-zA-Z]*\\(\\d+\\)\\s*=\\s*\\d+\\)";

for (String s : texts) {
    Pattern pattern = Pattern.compile(regex);
    Matcher matcher = pattern.matcher(s);
    if (matcher.find()) {
        System.out.println("There are match " + matcher.group());
    } else {
        System.out.println("No match occurred");
    }
}

Output

No match occurred
There are match (F(1) = 44)
No match occurred
No match occurred

regex demo