[SOLVED] Objective C: Creating Long Double uses Decimal Method

Objective C: Creating Long Double uses Decimal Method

How do I create the following method?

I have tried to use modf(n, 1) or modf(n, 2) but those both return an error of "Passing argument 2 of modf makes pointer from integer without a cast.

Heres the method:

(BOOL) numberHasDecimal: (long double) n {
    if (?????) // has decimal, like 16.300000 or 6453.353259
        return YES;
    else
        return NO; // has no decimal, like 58.000000 or 9274.000000
}

Solution

if (fabsl(fmodl(n, 1.0)) > 0.0) {
    // Has a decimal.
} else {
    // Is an integer.
}

Keep in mind that floating point values are internally rounded in counter-intuitive ways, so a number may have a very small fractional component and still appear integral when passed through fmodl().

Also note that Apple's implementation of Objective-C is broken when handling long double values, and may manifest difficult-to-track errors when you use them.