I want to pop up the ajax response by fancybox, I saw the network section in console, the response is ok. But I am getting $.fancybox is not a function. thanks in advance!
$("#mysubmit").click(function(){
var myvar = {
"secure_key":"41561541561561","username":$("#username").val(),"password" :$("#password").val()};
$.ajax({
type: "POST",
url: "http://127.0.0.1/ajaxtest.php",
async: false,
data: myvar,
success: (function (response) {
var result =
"<div id='result'>" +
"<p>" + response + "</p>" +
"</div>";
//$.facybox is not a function HERE
$.fancybox(result, {
type: "html",
}); // show formated response
})
})
});
FancyBox has to be instanciated on an element.
You actually try to instanciate it on jQuery...
Try this:
success: (function (response) {
var result =
"<div id='result'>" +
"<p>" + response + "</p>" +
"</div>";
$("body").append( $(result) );
$(document).find("#result").fancybox(); // show formated response
})