I've been echoing my way through the following code but I cannot determine why %ERRORLEVEL%
is always zero.
@echo off
set activePerl_SiteBinPath=D:\ProgramFiles\ActivePerl\site\bin
call :isInPath %activePerl_SiteBinPath% & set foundActivePerl_SiteBinPath=%ERRORLEVEL%
echo %foundActivePerl_SiteBinPath%
set blub=d:\blub
call :isInPath %blub% & set foundBlub=%ERRORLEVEL%
echo %foundBlub%
exit /b
:isInPath
:: Tests if the path stored within variable pathVar exists within %PATH%.
::
:: The result is returned as the ERRORLEVEL:
:: 0 if pathVar is found in %PATH%.
:: 1 if pathVar path is not found in %PATH%.
:: 2 if parhVar path is missing/undefined.
:: Error checking
if "%~1"=="" exit /b 2
set pathVar=%~1
for /f %%i in ('echo ";%%PATH%%;" ^| find /c /i ";%pathVar%;"') do (
set /a foundPathVar=%%i
)
if /i %foundPathVar% equ 0 (
exit /b 1
)
set foundPathVar=0
exit /b 0
I get the following output
0
0
but I would expect
0
1
and according to the echoing I did inside :isInPath
for case one exit /b 0
and for case two exit /b 1
is called. But why is %ERRORLEVEL%
zero in both cases? I totally don't get it. Please help!
In cmd the whole line will be parsed for variable substitution at once. Hence at the time the following line is executed errorlevel
is 0
call :isInPath %blub% & set foundBlub=%ERRORLEVEL%
You need to use delayed expansion
SETLOCAL EnableDelayedExpansion
call :isInPath %blub% & set foundBlub=!ERRORLEVEL!