At the moment, I have a working solution of a div (with a fixed height and width and a background image for the outer gradient border) and a pseudo element, positioned absolute
with a background image of the inner border.
.div {
position: relative;
width: 254px;
height: 254px;
border: 2px solid transparent;
border-radius: 50%;
background: url(../img/gradient_border_circle.png) no-repeat 50%;
}
div:before {
content: "";
position: absolute;
top: 50%;
transform: translate(-50%,-50%);
left: 50%;
width: 98px;
height: 98px;
border-radius: 50%;
background: url(../img/gradient_border_circle_inner.png) no-repeat 50%;
}
However, am looking for a more elegant solution (pure css or svg gradient?) without the use of background images where the gradient can scale with no pixelation.
I have researched and closest I have come across is https://codepen.io/nordstromdesign/pen/QNrBRM and Possible to use border-radius together with a border-image which has a gradient? But I need a solution where the centre is transparent in order to show through the page's background
Update: Ideally, am looking for a solution with relatively good support in all modern browsers.
SVG
is the recommended way to create a circle shape and draw gradient outline / border around it.
SVG
has a circle
element that can be used to draw a circle shape. This shape can be filled and outlined with a solid color, gradient or pattern.
* {box-sizing: border-box;}
body {
background: linear-gradient(#333, #999);
text-align: center;
min-height: 100vh;
padding-top: 10px;
margin: 0;
}
svg {vertical-align: top;}
<svg width="210" height="210">
<defs>
<linearGradient id="grad1" x1="0" y1="1" x2="1" y2="0">
<stop offset="0" stop-color="#f5d700" />
<stop offset="1" stop-color="#0065da" />
</linearGradient>
<linearGradient id="grad2" xlink:href="#grad1" x1="1" y1="0" x2="0" y2="1"></linearGradient>
</defs>
<g fill="none">
<circle cx="100" cy="100" r="95" stroke="url(#grad1)" stroke-width="2" />
<circle cx="100" cy="100" r="40" stroke="url(#grad2)" stroke-width="5" />
</g>
</svg>